Kodak grey card values

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a
Feb 28, 2004
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If I take a photograph of the 18% Reflectance side of a Kodak grey card and open the image in Photoshop. What values should I expect for RGB in the Info palette?

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G
Greg
Feb 29, 2004
Assuming the image is in the sRGB color space, and the image is white balanced accurately,
the RGB values would be about 119,119,119, according to this CIE Color Calculator:
http://www.brucelindbloom.com/ColorCalculator.html
I put in a Lab value of 50,0,0 (which I think corresponds to 50% reflectance). If you select "scale XYZ",
you can see that the resulting value for Y (which is Luminance) is close to 18, but not exactly 18.
(I’m not sure why there is this slight discrepancy).

You also need to select "scale RGB" in order for the resulting values to be scaled to the range 0-255.

The values will change according to the gamma of the color space the image is in.

Greg.
N
nomail
Feb 29, 2004
wrote:

If I take a photograph of the 18% Reflectance side of a Kodak grey card and open the image in Photoshop. What values should I expect for RGB in the Info palette?

If you want to cross post a message, do so by filling in all the newsgroups. That way, people who read the same groups, won’t see your message twice. Don’t post the same message separately in many newsgroups. Also, people who answer your message, will only need to write the answer once. I posted the answer in alt.graphics.photoshop:

18% reflectance is 18% L in the LAB mode. If you fill in 18,0,0 in LAB, you’ll get RGB 48,48,48.


Johan W. Elzenga johan<<at>>johanfoto.nl Editor / Photographer http://www.johanfoto.nl/
G
Greg
Feb 29, 2004
"Johan W. Elzenga" wrote in message
18% reflectance is 18% L in the LAB mode. If you fill in 18,0,0 in LAB, you’ll get RGB 48,48,48.

I don’t think that’s right. I think 18% reflectance is 18% *absolute* reflectance, which
corresponds to middle grey, which is a Lab luminance of 50.

Greg.
N
nomail
Feb 29, 2004
Greg wrote:

"Johan W. Elzenga" wrote in message
18% reflectance is 18% L in the LAB mode. If you fill in 18,0,0 in LAB, you’ll get RGB 48,48,48.

I don’t think that’s right. I think 18% reflectance is 18% *absolute* reflectance, which
corresponds to middle grey, which is a Lab luminance of 50.

You are right. It’s 1.41 hours AM here, so I wasn’t thinking too clearly.


Johan W. Elzenga johan<<at>>johanfoto.nl Editor / Photographer http://www.johanfoto.nl/
G
Greg
Feb 29, 2004
I wrote:
I put in a Lab value of 50,0,0 (which I think corresponds to 50% reflectance). If you select "scale XYZ",
you can see that the resulting value for Y (which is Luminance) is close
to
18, but not exactly 18.
(I’m not sure why there is this slight discrepancy).

I guess the reason for this slight discrepancy is that middle grey really is 18.418652….%
reflectance, but it’s rounded down to 18% for convenience?

Greg.
CC
Chris Cox
Feb 29, 2004
In article <1g9w8p5.1hj4bl313nbjk0N%>, Johan W.
Elzenga wrote:

wrote:

If I take a photograph of the 18% Reflectance side of a Kodak grey card and open the image in Photoshop. What values should I expect for RGB in the Info palette?

If you want to cross post a message, do so by filling in all the newsgroups. That way, people who read the same groups, won’t see your message twice. Don’t post the same message separately in many newsgroups. Also, people who answer your message, will only need to write the answer once. I posted the answer in alt.graphics.photoshop:
18% reflectance is 18% L in the LAB mode. If you fill in 18,0,0 in LAB, you’ll get RGB 48,48,48.

No – 18% reflectance is close to 50 % in L*.
Reflectance is not the same thing as perceived gray values. (because of the logarithm/power law in human vision)

Chris
A
a
Feb 29, 2004
My apologies for the crossposting, thats the first (and last) time I’ll do that.

And, if anyone else needs a reason NOT to crosspost – It’s because you end up with intelligent, knowledgeable people NOT being able to engage in a structured conversation and NOT being able to develop their arguments with each other.

The idea behind the original question was this:

If I expose a roll of film and load the images into Photoshop with one exposure a picture of an 18% reflectance grey card, what should the RGB values be in the Info pallete? The consensus seems to be approx R=119, G=119 and B=119. If I then correct any discrepancies – can I apply the same correction to the rest of the roll of film?
H
hoffmann
Feb 29, 2004
"Greg" …
Assuming the image is in the sRGB color space, and the image is white balanced accurately,
the RGB values would be about 119,119,119, according to this CIE Color Calculator:
http://www.brucelindbloom.com/ColorCalculator.html
I put in a Lab value of 50,0,0 (which I think corresponds to 50% reflectance). If you select "scale XYZ",
you can see that the resulting value for Y (which is Luminance) is close to 18, but not exactly 18.
(I’m not sure why there is this slight discrepancy).

You also need to select "scale RGB" in order for the resulting values to be scaled to the range 0-255.

The values will change according to the gamma of the color space the image is in.

Greg.

These are the formulas:

L*=50
Y1=(L*+16)/116 = 0.569
If Y1>0.207 Then
Y=Y1^3 = 0.184
Aha, the physical luminance or reflectance is 0.184 of 0…1. For sRGB:
If Y>0.00304 Then
R´=G´=B´=255*[1.055*Y^(1/2.4)-0.055]=118.8
These are the numbers in the file for the working space sRGB. An arbitrary working space with G=2.2 would deliver
R´=G´=B´=255*Y^(1/2.2)=118.1

Visualization of 100 gray patches with CIELab and sRGB numbers on page 6 (200kB doc):
http://www.fho-emden.de/~hoffmann/a3gencolortest.pdf

It´s up to everybody which gray should be considered as "medium".

Best regards –Gernot Hoffmann
N
nomail
Feb 29, 2004
wrote:

My apologies for the crossposting, thats the first (and last) time I’ll do that.

And, if anyone else needs a reason NOT to crosspost – It’s because you end up with intelligent, knowledgeable people NOT being able to engage in a structured conversation and NOT being able to develop their arguments with each other.

There is nothing wrong with crossposting to two groups, as long as you do it properly. Write ONE message, and set both groups in the newsgroup header of that message. That way, your message will appear in both groups, and all answers will also automatically appear in both groups.


Johan W. Elzenga johan<<at>>johanfoto.nl Editor / Photographer http://www.johanfoto.nl/
C
cantexadian
Mar 1, 2004
wrote in message news:…
My apologies for the crossposting, thats the first (and last) time I’ll do that.

And, if anyone else needs a reason NOT to crosspost – It’s because you end up with intelligent, knowledgeable people NOT being able to engage in a structured conversation and NOT being able to develop their arguments with each other.

The idea behind the original question was this:

If I expose a roll of film and load the images into Photoshop with one exposure a picture of an 18% reflectance grey card, what should the RGB values be in the Info pallete? The consensus seems to be approx R=119, G=119 and B=119. If I then correct any discrepancies – can I apply the same correction to the rest of the roll of film?

————————————–

There is a discussion on 18% grey card values at

http://photoshopgurus.info/forum/viewtopic.php?t=4448

and they come up with RGB values of 209,209,209 using some very sound arguements and pictures(especially from Rantin Al)
What is going on.
nikki
G
Greg
Mar 1, 2004
"nikki" wrote in message
There is a discussion on 18% grey card values at

http://photoshopgurus.info/forum/viewtopic.php?t=4448

and they come up with RGB values of 209,209,209 using some very sound arguements and pictures(especially from Rantin Al)

I haven’t tried to follow the whole thread in detail yet, but some of the reasoning just doesn’t seem right.

I’ve just taken a photo of my white wall with my digicam after calibrating the white balance,
and the result is a lot closer to that predicted in our thread here. The wall was not evenly
lit (but not terribly uneven, either). Centre pixel values are about 139,140,138
corner pixel values 100,101,102, and if the entire image is averaged, the result is 122,123,122.
(a simple average like this isn’t totally valid, because the camera was set for centre weighted
average – I didn’t apply any weighting)

The values predicted in that thread, at least for a typical gamma RGB space, just seem way too high.

Greg.
G
Greg
Mar 1, 2004
Forgot to specify the colour space of the digicam image – the camera outputs in sRGB, and I left
the image in sRGB when importing into Photoshop.

Greg.
"Greg" wrote in message
"nikki" wrote in message
There is a discussion on 18% grey card values at

http://photoshopgurus.info/forum/viewtopic.php?t=4448

and they come up with RGB values of 209,209,209 using some very sound arguements and pictures(especially from Rantin Al)

I haven’t tried to follow the whole thread in detail yet, but some of the reasoning just doesn’t seem right.

I’ve just taken a photo of my white wall with my digicam after calibrating the white balance,
and the result is a lot closer to that predicted in our thread here. The wall was not evenly
lit (but not terribly uneven, either). Centre pixel values are about 139,140,138
corner pixel values 100,101,102, and if the entire image is averaged, the result is 122,123,122.
(a simple average like this isn’t totally valid, because the camera was
set
for centre weighted
average – I didn’t apply any weighting)

The values predicted in that thread, at least for a typical gamma RGB
space,
just seem way too high.

Greg.

C
cantexadian
Mar 1, 2004
"Greg" …
"nikki" wrote in message
There is a discussion on 18% grey card values at

http://photoshopgurus.info/forum/viewtopic.php?t=4448

and they come up with RGB values of 209,209,209 using some very sound arguements and pictures(especially from Rantin Al)

I haven’t tried to follow the whole thread in detail yet, but some of the reasoning just doesn’t seem right.

I’ve just taken a photo of my white wall with my digicam after calibrating the white balance,
and the result is a lot closer to that predicted in our thread here. The wall was not evenly
lit (but not terribly uneven, either). Centre pixel values are about 139,140,138
corner pixel values 100,101,102, and if the entire image is averaged, the result is 122,123,122.
(a simple average like this isn’t totally valid, because the camera was set for centre weighted
average – I didn’t apply any weighting)

The values predicted in that thread, at least for a typical gamma RGB space, just seem way too high.

Greg.
——————————–
Greg

I thought so too , at first, but the tests I have made indicate the RGB value is higher than the the RGB 122,122,122 you indicate. You can make a wall into any value by just changing any of a dozen parameters. I don’t think empirical testing, without controls, is valid. I did a test and the histogram data seems to indicate a higher RGB value than the one you predicted.(Above the RGB 150,150,150 value). I think the key here is refelectance, not grey value(18% grey to be exact). I hope there is a Color scientist out there who is also a PS user.

nikki

Greg
S
saswss
Mar 1, 2004
In article ,
"Greg" writes:
"nikki" wrote in message
There is a discussion on 18% grey card values at

http://photoshopgurus.info/forum/viewtopic.php?t=4448

and they come up with RGB values of 209,209,209 using some very sound arguements and pictures(especially from Rantin Al)

I haven’t tried to follow the whole thread in detail yet, but some of the reasoning just doesn’t seem right.

I’ve just taken a photo of my white wall with my digicam after calibrating the white balance,
and the result is a lot closer to that predicted in our thread here. The wall was not evenly
lit (but not terribly uneven, either). Centre pixel values are about 139,140,138

There is no single answer to this question because it all depends on the brightness range of the subject and what you want the image to look like. Pixel values around 140 are reasonable for typical low-contrast scenes, and in fact my 3 digital cameras also yield values around 140 for a subject with constant brightness.

The gurus are very confused.


Warren S. Sarle SAS Institute Inc. The opinions expressed here SAS Campus Drive are mine and not necessarily
(919) 677-8000 Cary, NC 27513, USA those of SAS Institute.
G
Greg
Mar 1, 2004
"nikki" wrote in message
I thought so too , at first, but the tests I have made indicate the RGB value is higher than the the RGB 122,122,122 you indicate.

Are you willing to provide details of your tests?

I hope there is a Color scientist out there who is also a PS user.

Well, Chris Cox has already replied in our thread here, and his name is on the Photoshop
author’s list. I don’t know whether he’s a color scientist, though. ;^)

Greg.
L
llutton
Mar 2, 2004
I’ve always figured 127, 127, 127 as the colors for a gray card. Maybe it varies with a different gamma setting but I use 220 which is the Windows default. If you’re using a Mac, set it to 180.

Try this:
1. Select a rectangular shape
2. Set the default foreground/background
colors by typing a "D".
3. Click on the Gradient tool and drag a
horizontal line across the selection.
4. Image > Adjustments > Posterize
(use an uneven number, like 5).
5. With the info box open, notice the
numbers 127 appear in triplicate. If not,
click on the eyedropper in the Info box
and select "Actual Color".
Lynn
G
Greg
Mar 2, 2004
"Warren Sarle" wrote in message
The gurus are very confused.

The folks over in that web forum are very confused, IMHO. Not the gurus in this thread. ;^)

Greg.
G
Greg
Mar 2, 2004
There’s no need to do all that. If you can accept that the L* value for middle grey is 50 (on a scale of 0 to 100),
just use the CIE Color calculator (as I said earlier). Punch in 50,0,0 in the L*a*b* fields and you can see that the resulting pixel values in sRGB are 119,119,119. The L* scale is perceptually uniform – that’s why half scale (50) represents middle grey, exactly. The fact that the resulting pixel values (in sRGB) are not *exactly*
half scale just means that sRGB is not *exactly* perceptually uniform. In any case, 127,127,127, is less
than a fifth of a stop difference from 119,119,119, so yes, 127,127,127 is almost middle grey.

Greg.

"LLutton" wrote in message
I’ve always figured 127, 127, 127 as the colors for a gray card. Maybe it varies with a different gamma setting but I use 220 which is the Windows default. If you’re using a Mac, set it to 180.

Try this:
1. Select a rectangular shape
2. Set the default foreground/background
colors by typing a "D".
3. Click on the Gradient tool and drag a
horizontal line across the selection.
4. Image > Adjustments > Posterize
(use an uneven number, like 5).
5. With the info box open, notice the
numbers 127 appear in triplicate. If not,
click on the eyedropper in the Info box
and select "Actual Color".
Lynn
G
Greg
Mar 2, 2004
I wrote:
Centre pixel values are about
139,140,138
corner pixel values 100,101,102, and if the entire image is averaged, the result is 122,123,122.
(a simple average like this isn’t totally valid, because the camera was
set
for centre weighted
average – I didn’t apply any weighting)

I repeated this test, using spot metering instead, to reduce the effect of the uneven lighting.
The resulting pixel values in the centre of the image are now about: 132,133,131. Camera is a
consumer digicam (Nikon Coolpix 4300).

Greg.
G
Greg
Mar 2, 2004
This web page provides another data point for middle grey reproduction: http://www.botzilla.com/photo/g1expose.html
(looks like about 132 for this chap’s Canon G1)

Greg.
W
westin*nospam
Mar 2, 2004
"Greg" writes:

There’s no need to do all that. If you can accept that the L* value for middle grey is 50 (on a scale of 0 to 100),

Not really. The 18% was chosen on midway on a logarithmic scale between a very low reflectance value (remember, log(0) isn’t a real number) and an ideal Lambertian reflector. L*a*b* uses a cube root as its nonlinearity, rathern than logarithm. So there’s no reason to think that the middle of the two scales would correspond.

Besides which, making an ideal Lambertian reflector the top of your scale will mean clipping anything brighter than that. And, since the world isn’t Lambertian (i.e. ideally diffuse), there’s plenty out there that’s brighter.

I think obsessing about this is pointless. After all, it’s just a starting point for variations in exposure a la Ansel Adams.

just use the CIE Color calculator (as I said earlier). Punch in 50,0,0 in the L*a*b* fields and you can see that the resulting pixel values in sRGB are 119,119,119. The L* scale is perceptually uniform

In an approximate way, just as all mathematical representations of color and brightness are. The Munsell scale is perceptually uniform for diffuse surfaces under certain conditions, but there’s no closed-form mathematical formulation for it.

Really, the nonlinearity of brightness perception has been measured as a number of different nonlinear functions; logarithm, square root, cube root, and others, depending on viewing conditions.

– that’s why half
scale (50) represents middle grey, exactly. The fact that the resulting pixel values (in sRGB) are not *exactly*
half scale just means that sRGB is not *exactly* perceptually uniform.

It wasn’t intended to be. It’s an idealized display characteristic.

<snip>


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
G
Greg
Mar 2, 2004
"Stephen H. Westin" <westin*> wrote in message
Not really. The 18% was chosen on midway on a logarithmic scale between a very low reflectance value (remember, log(0) isn’t a real number) and an ideal Lambertian reflector. L*a*b* uses a cube root as its nonlinearity, rathern than logarithm. So there’s no reason to think that the middle of the two scales would correspond.

Ok – thanks. I thought the middle grey value of 18(.4…)% was in fact derived
from a L* value of 50 – sorry.

– that’s why half
scale (50) represents middle grey, exactly. The fact that the resulting pixel values (in sRGB) are not *exactly*
half scale just means that sRGB is not *exactly* perceptually uniform.

It wasn’t intended to be. It’s an idealized display characteristic.

Ok. I didn’t mean to imply that sRGB was *meant* to be exactly perceptually uniform – I’m just stating that it’s not. It is generally accepted that gamma 2.2
is "substantially" perceptually uniform. (and sRGB has a gamma of 2.2, of course)
However, my reasoning for stating this is obviously flawed anyway, after your
explanation of how Lab space isn’t necessarily exactly perceptually uniform anyway.

Greg.
G
Greg
Mar 2, 2004
"Stephen H. Westin" <westin*> wrote in message
"Greg" writes:

There’s no need to do all that. If you can accept that the L* value for middle grey is 50 (on a scale of 0 to 100),

Not really. The 18% was chosen on midway on a logarithmic scale between a very low reflectance value (remember, log(0) isn’t a real number) and an ideal Lambertian reflector. L*a*b* uses a cube root as its nonlinearity, rathern than logarithm. So there’s no reason to think that the middle of the two scales would correspond.

Just to add to my previous reply to this, despite the fact L*=50 doesn’t match up *exactly* to 18% reflection, they very nearly do match, and the basic logic of using the CIE Color Calculator to work out middle grey in RGB should still be valid. (yes?!?)

If it weren’t for that web forum saying that middle grey is 209, I wouldn’t be "obsessing" over this so much. 209 just seems way too high.

If we can generally agree that the grey card should be represented by RGB pixels of around about mid-scale (circa 128) in a perceptually uniform colour space
such as sRGB, that would sit fine with me. ;^)

Greg.

Greg.

Besides which, making an ideal Lambertian reflector the top of your scale will mean clipping anything brighter than that. And, since the world isn’t Lambertian (i.e. ideally diffuse), there’s plenty out there that’s brighter.

I think obsessing about this is pointless. After all, it’s just a starting point for variations in exposure a la Ansel Adams.
just use the CIE Color calculator (as I said earlier). Punch in 50,0,0
in
the L*a*b* fields and you can see that the resulting pixel values in
sRGB
are 119,119,119. The L* scale is perceptually uniform

In an approximate way, just as all mathematical representations of color and brightness are. The Munsell scale is perceptually uniform for diffuse surfaces under certain conditions, but there’s no closed-form mathematical formulation for it.

Really, the nonlinearity of brightness perception has been measured as a number of different nonlinear functions; logarithm, square root, cube root, and others, depending on viewing conditions.

– that’s why half
scale (50) represents middle grey, exactly. The fact that the resulting pixel values (in sRGB) are not *exactly*
half scale just means that sRGB is not *exactly* perceptually uniform.

It wasn’t intended to be. It’s an idealized display characteristic.
<snip>


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
G
Greg
Mar 2, 2004
Could the reason that our digital cameras seem to produce a middle grey about a third
to a half a stop (or more for some?) above the theoretical/pure middle grey be something to do with
the dynamic range actually achievable by the camera? I.e, are the camera manufacturers placing
middle grey mid-way between the noise floor and full scale, rather than mid way between zero
and full scale?

Greg.
p.s Going to bed now – now more obsessing until tomorrow.
S
saswss
Mar 2, 2004
In article <40449d75$>,
"Greg" writes:
Could the reason that our digital cameras seem to produce a middle grey about a third
to a half a stop (or more for some?) above the theoretical/pure middle grey be something to do with
the dynamic range actually achievable by the camera? I.e, are the camera manufacturers placing
middle grey mid-way between the noise floor and full scale, rather than mid way between zero
and full scale?

Something along those lines seems likely to me.
Most manufacturers calibrate their light meters according to ANSI Standard ANSI/ISO 2720-1974 (R1994), ANSI/NAPM IT3.302-1994, which is not readily available to the public. I don’t know of standards for converting raw data to specific color spaces. —

Warren S. Sarle SAS Institute Inc. The opinions expressed here SAS Campus Drive are mine and not necessarily
(919) 677-8000 Cary, NC 27513, USA those of SAS Institute.
G
Greg
Mar 2, 2004
Thanks. I’ve actually just stumbled on this document:
http://members.cox.net/dspielman1/Gray_Card/ANSI_PH3_49_1971 .PDF which actually throws another spanner into the works – apparently camera lightmeters
are typically calibrated for 12 to 13% grey! That would mean that the RGB values
we’re getting are even *further* from the theoretical prediction. Arrgh.

Greg.

"Warren Sarle" wrote in message
In article <40449d75$>,
"Greg" writes:
Could the reason that our digital cameras seem to produce a middle grey about a third
to a half a stop (or more for some?) above the theoretical/pure middle
grey
be something to do with
the dynamic range actually achievable by the camera? I.e, are the camera manufacturers placing
middle grey mid-way between the noise floor and full scale, rather than
mid
way between zero
and full scale?

Something along those lines seems likely to me.
Most manufacturers calibrate their light meters according to ANSI Standard ANSI/ISO 2720-1974 (R1994), ANSI/NAPM IT3.302-1994, which is not readily available to the public. I don’t know of standards for converting raw data to specific color spaces. —

Warren S. Sarle SAS Institute Inc. The opinions expressed here SAS Campus Drive are mine and not necessarily
(919) 677-8000 Cary, NC 27513, USA those of SAS Institute.
F
Flycaster
Mar 2, 2004
"Greg" wrote in message
Thanks. I’ve actually just stumbled on this document:
http://members.cox.net/dspielman1/Gray_Card/ANSI_PH3_49_1971 .PDF which actually throws another spanner into the works – apparently camera lightmeters
are typically calibrated for 12 to 13% grey! That would mean that the RGB values
we’re getting are even *further* from the theoretical prediction. Arrgh.

Having now followed this same thread in 3 different NG’s, and in 2 high end forums, in which all the supposed cognoscenti and experts weighed in…all drawing sometimes vastly different conclusions resulting in "numbers" literally all over the board, it might be well advised to just throw in the towel on this one!

I mean, does it really matter? (it certainly has no impact on how I shoot or use PS, but perhaps I’m simply ignorant, and blissfully so.)

—–= Posted via Newsfeeds.Com, Uncensored Usenet News =—– http://www.newsfeeds.com – The #1 Newsgroup Service in the World! —–== Over 100,000 Newsgroups – 19 Different Servers! =—–
G
Greg
Mar 2, 2004
"Flycaster" wrote in message
it might be well advised to just throw in the
towel on this one!

You’re probably right. But I’m going to try my luck and email Nikon technical support. ;^)

Greg.
J
JJS
Mar 2, 2004
"Greg" wrote in message
"Flycaster" wrote in message
it might be well advised to just throw in the
towel on this one!

You’re probably right. But I’m going to try my luck and email Nikon technical support. ;^)

Why do you need to know 12% (or 18%) grey? Just curious. Film photographers do not use it as an absolute of anything, except to bit-twiddle their light meters, and that’s usually futile because many of them don’t use the ‘standard’ light source nor the ‘standard’ angle of viewing of the card. It just gives them an excuse to bullsiht on Usenet instead of making pictures.

Professionals use a grey card as a point-of-departure to calibrate our own equipment (lighting, shutters, darkroom, color) work, and lab people use it to calibrate across devices. But it’s still not an absolute of anything. It is relative to applications.

Buy the Kodak Grey Card pack. It’s got cards with black, white and "18%" grey. It’s got to be under $20us.

Also get another card with a tone scale and color scale – and photograph it with your digital camera. If you can make a straight DIGITAL print of the color that is _truly_ representative of those samples, then I’ll pop for beverages of your choice.
J
JJS
Mar 2, 2004
My mate just reminded me that grey is spelled G-R-A-Y here. 🙂 Sorry.
G
Greg
Mar 2, 2004
"jjs" wrote in message
Why do you need to know 12% (or 18%) grey? Just curious.

Because.

Buy the Kodak Grey Card pack. It’s got cards with black, white and "18%" grey. It’s got to be under $20us.

Also get another card with a tone scale and color scale – and photograph
it
with your digital camera. If you can make a straight DIGITAL print of the color that is _truly_ representative of those samples, then I’ll pop for beverages of your choice.

There’s no way I could do that with my consumer digicam, because it is limited to
sRGB to start with. Many patches of an IT8 chart are simply out of the camera’s
gamut.

Greg.
F
Flycaster
Mar 2, 2004
"jjs" wrote in message
My mate just reminded me that grey is spelled G-R-A-Y here. 🙂 Sorry.

Our dictionaries allow both spellings…you’re safe. 😉

—–= Posted via Newsfeeds.Com, Uncensored Usenet News =—– http://www.newsfeeds.com – The #1 Newsgroup Service in the World! —–== Over 100,000 Newsgroups – 19 Different Servers! =—–
G
Greg
Mar 3, 2004
"jjs" wrote in message
My mate just reminded me that grey is spelled G-R-A-Y here. 🙂 Sorry.

I’ve been remembering to include both spellings in my Google searches. ;^) (*nothing* is simple!)

Greg.
G
Greg
Mar 3, 2004
Besides, typical cameras aren’t designed to capture/reproduce scenes linearly – they are designed to produce
pleasing results. But, I thought middle grey was supposed to be reproduced as middle grey – I thought it was
a constant, regardless of other tonal adjustments might be made, either by a digital camera, or film characteristics.

Perhaps some digital cameras in RAW mode can record scenes purely linearly?

Greg.
"Greg" wrote in message
"jjs" wrote in message
Why do you need to know 12% (or 18%) grey? Just curious.

Because.

Buy the Kodak Grey Card pack. It’s got cards with black, white and "18%" grey. It’s got to be under $20us.

Also get another card with a tone scale and color scale – and photograph
it
with your digital camera. If you can make a straight DIGITAL print of
the
color that is _truly_ representative of those samples, then I’ll pop for beverages of your choice.

There’s no way I could do that with my consumer digicam, because it is limited to
sRGB to start with. Many patches of an IT8 chart are simply out of the camera’s
gamut.

Greg.

W
westin*nospam
Mar 3, 2004
"Flycaster" writes:

"Greg" wrote in message
Thanks. I’ve actually just stumbled on this document:
http://members.cox.net/dspielman1/Gray_Card/ANSI_PH3_49_1971 .PDF which actually throws another spanner into the works – apparently camera lightmeters
are typically calibrated for 12 to 13% grey! That would mean that the RGB values
we’re getting are even *further* from the theoretical prediction. Arrgh.

Having now followed this same thread in 3 different NG’s, and in 2 high end forums, in which all the supposed cognoscenti and experts weighed in…all drawing sometimes vastly different conclusions resulting in "numbers" literally all over the board, it might be well advised to just throw in the towel on this one!

I mean, does it really matter? (it certainly has no impact on how I shoot or use PS, but perhaps I’m simply ignorant, and blissfully so.)

Well, in traditional photography it serves as a placemarker for the middle of the brightness range: your camera/film/printing system will generally reproduce middle gray +- N stops. As I recall, the Zone System puts N at about 4. So you try to expose so as to get the "important" parts of the image in that range, and manipulate development and printing to put that brightness range where you want it. But Adams was very big on testing everything to *put* that 18% gray in the middle as a reference point, rather than assuming that manufacturers of meter, film, camera, etc. have done all the work for you. It’s perfectly plausible to me that different cameras would put the "properly exposed" gray card at somewhat different numerical values; if you’re really serious, the important part is understanding your imaging pipeline and how to control it to get the results you want.


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
TE
Tom Elliott
Mar 3, 2004
Thread deleted for brevity.
So, I would think that grey/color bar is immaterial for the taking of the shot because you can view
the shot on the LCD view finder and tell if the colors are where you want. I guess you could include
the cards on the edge or one frame in the light you are using for a printing reference if a stranger
had to make your print and there was no white with texture to reference to. Also to use the cards to
calibrate your CRT and printer.
I have a calibration file from my service bureau that I calibrate my screen and my printer to match
their hard copy print they include with the digital file. How many out there are using their own dark room? I have not been in the dark room to make a print since 1992 and I have both feet in the analogue and digital world. Yours,
Tom
G
Greg
Mar 3, 2004
"Stephen H. Westin" <westin*> wrote in message
It’s perfectly plausible to me that
different cameras would put the "properly exposed" gray card at somewhat different numerical values;

Yes, of course, but it is puzzling me a bit as to why the results so far seem to be consistently somewhat
above the theoretical mid-point of the luminance scale. I’m mindful of what you said
about there being different formulas for the perceptually uniform luminance scale – if the
camera manufacturers do use a different scale (to that used in Bruce Lindbloom’s CIE Color Calculator), it would
be interesting to know what it is.

I realise that if we were to test more cameras, we *may* start to move the *average* result
down to the theoretical midpoint, though.

Greg.
W
westin*nospam
Mar 3, 2004
"Greg" writes:

"Stephen H. Westin" <westin*> wrote in message
It’s perfectly plausible to me that
different cameras would put the "properly exposed" gray card at somewhat different numerical values;

Yes, of course, but it is puzzling me a bit as to why the results so far seem to be consistently somewhat
above the theoretical mid-point of the luminance scale. I’m mindful of what you said
about there being different formulas for the perceptually uniform luminance scale – if the
camera manufacturers do use a different scale (to that used in Bruce Lindbloom’s CIE Color Calculator), it would
be interesting to know what it is.

Ansel Adams pointed out that some manufacturers of light meters intentionally miscalibrate their meters to try to create a margin for error for the typical user. I suspect the same thing is going on with digital cameras: instead of strictly "accurate" meter calibration, manufacturers may bias the exposure so that most of the time, the picture looks better to the eye.

<snip>


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
W
westin*nospam
Mar 3, 2004
Tom Elliott writes:

Thread deleted for brevity.
So, I would think that grey/color bar is immaterial for the taking of the shot because you can view the shot on the LCD view finder and tell if the colors are where you want.

Not really. No one claims that the on-camera LCD is an accurate prediction of what the image will look like when printed, or even when displayed on a good monitor. It’s more to check framing.

I guess you could include the cards
on the edge or one frame in the light you are using for a printing reference if a stranger had to make your print and there was no white with texture to reference to. Also to use the cards to calibrate your CRT and printer.

Or if you just want predictable results so you can control reproduction of shadows vs. highlights.

I have a calibration file from my service bureau that I calibrate my screen and my printer to match their hard copy print they include with the digital file.
How many out there are using their own dark room? I have not been in the dark room to make a print since 1992 and I have both feet in the analogue and digital world.


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
J
JJS
Mar 3, 2004
"Greg" wrote in message
"jjs" wrote in message
[…]
If you can make a straight DIGITAL print of the
color that is _truly_ representative of those samples, then I’ll pop for beverages of your choice.

There’s no way I could do that with my consumer digicam, because it is limited to sRGB to start with. Many patches of an IT8 chart are simply out
of the
camera’s gamut.

Bummer! I’d rather lose the bet than learn that.
J
JJS
Mar 3, 2004
"Tom Elliott" wrote in message
Thread deleted for brevity.
So, I would think that grey/color bar is immaterial for the taking of the
shot because you can view
the shot on the LCD view finder and tell if the colors are where you want.

[…]

That is far from true. There are profound shortcomings concerning color rendition and calibration of workstation displays, and I suspect hell will freeze over before there’s a good little LCD.
J
JJS
Mar 3, 2004
"Stephen H. Westin" <westin*> wrote in message

Ansel Adams pointed out that some manufacturers of light meters intentionally miscalibrate their meters to try to create a margin for error for the typical user. […]

That was a long time ago. True that early meters had no standard to go by, and many manufacturers included reference cards with suggested film speeds for various films of the time. Weston meter calibrations were changed to be less optomistic at one point; I believe when color film became popular (for the Weston Model III, I think.)

Today the variance in meters is largely due to poor manufacturing control. IMHO!
W
westin*nospam
Mar 3, 2004
"jjs" writes:

"Tom Elliott" wrote in message
Thread deleted for brevity.
So, I would think that grey/color bar is immaterial for the taking of the
shot because you can view
the shot on the LCD view finder and tell if the colors are where you want.

[…]

That is far from true. There are profound shortcomings concerning color rendition and calibration of workstation displays, and I suspect hell will freeze over before there’s a good little LCD.

I think that’s an exaggeration, but perfect color rendition is rather far down the list for a camera LCD. First would be low power consumption, then overall size, etc. And of course the viewing conditions are so variable that even the best LCD (or CRT) would be unreliable. There’s a reason for those histogram displays and the digital point densitometer on the Kodak SLR’s.


-Stephen H. Westin
Any information or opinions in this message are mine: they do not represent the position of Cornell University or any of its sponsors.
G
Greg
Mar 3, 2004
"jjs" wrote in message
There’s no way I could do that with my consumer digicam, because it is limited to sRGB to start with. Many patches of an IT8 chart are simply
out
of the
camera’s gamut.

Bummer! I’d rather lose the bet than learn that.

Yes, well, I’m probably exaggerating a bit. Despite the fact that Photoshop reports
many of the patches being out of gamut (correctly, I think), most of them still *look*
very accurate on my calibrated monitor, which would have a gamut quite close to sRGB.

Greg.

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